QJEEM19Ma372f: JEE Main 2019 Mathematics - Class 12 JEEM19Ma372f Solution: The area (in sq. units) in the first quadrant bounded by the…

Question

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The area (in sq. units) in the first quadrant bounded by the parabola, y = x² + 1, the tangent to it at the point (2, 5) and the coordinate axes is :

Accepted Answer

Area

= \int_{0}^{2} (x^{2} + 1) d x - \frac{1}{2} (\frac{5}{4}) (5) = \frac{37}{24}

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