Verified Solution • 2025–26 Session moderate

QJEEM19Ma35f3: JEE Main 2019 Mathematics - Class 11 JEEM19Ma35f3 Solution: If , then (1 + iz + z 5 + iz 8 ) 9 is equal to :

If z=32+i2(i=−1)z = {{\sqrt 3 } \over 2} + {i \over 2}\left( {i = \sqrt { - 1} } \right) ,

then (1 + iz + z5 + iz8)9 is equal to :

Multiple Choice Options

  • A 1
  • B –1
  • C 0
  • D (-1 + 2i)9

Step-by-Step Verified Solution

z=32+i2z = {{\sqrt 3 } \over 2} + {i \over 2}

⇒\Rightarrow z = cos⁡π6\cos {\pi \over 6} + i sin⁡π6\sin {\pi \over 6}

⇒\Rightarrow z = eiπ6{e^{i{\pi \over 6}}} JEE Main 2019 (Online) 8th April Evening Slot Mathematics - Complex Numbers Question 135 English Explanation

Related Learning Resources & Exam Preparation