Verified Solution • 2025–26 Session moderate

QJEEM19Ma1ae3: JEE Main 2019 Mathematics - Class 11 JEEM19Ma1ae3 Solution: If is a purely imaginary number and

If z−αz+α(α∈R){{z - \alpha } \over {z + \alpha }}\left( {\alpha \in R} \right) is a purely imaginary number and | z | = 2, then a value of α\alpha is :

Multiple Choice Options

  • A 12{1 \over 2}
  • B 2\sqrt 2
  • C 2
  • D 1

Step-by-Step Verified Solution

z−αz+α+z‾−αz‾+α=0{{z - \alpha } \over {z + \alpha }} + {{\overline z - \alpha } \over {\overline z + \alpha }} = 0

zz‾+zα−αz‾−α2+zz‾−zα+z‾α−α2=0z\overline z + z\alpha - \alpha \overline z - {\alpha ^2} + z\overline z - z\alpha + \overline z \alpha - {\alpha ^2} = 0

∣z∣2=α2,{\left| z \right|^2} = {\alpha ^2},    a=±2a = \pm 2

Related Learning Resources & Exam Preparation