QJEEM19Ma194a: JEE Main 2019 Mathematics - Class 11 JEEM19Ma194a Solution: Two newspapers A and B are published in a city. It is known…

The total population to be 100 (for simplicity's sake) and the percentages can be treated as actual numbers of people in this context.

The percentage of people who read newspaper A is given as 25. However, among these, there are people who read both newspapers A and B, given as 8. To find the number of people who read only newspaper A, we subtract the number of people who read both from the total number of people who read A. That is,

n(A only) = 25 – 8 = 17

Similarly, the number of people who read only newspaper B is calculated as :

n(B only) = 20 – 8 = 12

Now, we are given the percentage of each of these groups that look into the advertisements:

• 30% of those who read A but not B,
• 40% of those who read B but not A,
• 50% of those who read both A and B.

To find the total percentage of the population that looks into advertisements, we add up the contributions from each of these groups. We calculate each group's contribution by multiplying the size of the group by the percentage of that group that looks at advertisements :

= $$\frac{30}{100}\times 17$$ (from A only) + $$\frac{40}{100}\times 12$$(from B only) + $$\frac{50}{100}\times 8$$(from both A and B)

= 5.1 (from A only) + 4.8 (from B only) + 4 (from both A and B)

Adding these up, we get

= 13.9

This means that 13.9% of the total population looks into the advertisements.

So, the correct answer is :

Option D : 13.9.