Verified Solution • 2025–26 Session moderate

QJEEM19Ma0348: JEE Main 2019 Mathematics - Class 11 JEEM19Ma0348 Solution: The outcome of each of 30 items was observed; 10 items gave an…

The outcome of each of 30 items was observed; 10 items gave an outcome 12{1 \over 2} – d each, 10 items gave outcome 12{1 \over 2} each and the remaining 10 items gave outcome 12{1 \over 2} + d each. If the variance of this outcome data is 43{4 \over 3} then |d| equals :

Multiple Choice Options

  • A 23{2 \over 3}
  • B 52{{\sqrt 5 } \over 2}
  • C 2{\sqrt 2 }
  • D 2

Step-by-Step Verified Solution

Variance is independent of region. So we shift the given data by 12{1 \over 2} .

so,    10d2+10×02+10d230−(0)2=43{{10{d^2} + 10 \times {0^2} + 10{d^2}} \over {30}} - {\left( 0 \right)^2} = {4 \over 3}

⇒\Rightarrow   d2 == 2 ⇒\Rightarrow   ∣d∣=2\left| d \right| = \sqrt 2

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