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QJEEM19Ma01f3: JEE Main 2019 Mathematics - Class 11 JEEM19Ma01f3 Solution: If the fractional part of the number , then k is equal to :

If the fractional part of the number {240315}is k15\left\{ {{{{2^{403}}} \over {15}}} \right\} is \, {k \over {15}} , then k is equal to :

Multiple Choice Options

  • A 8
  • B 14
  • C 6
  • D 1

Step-by-Step Verified Solution

240315{{{2^{403}}} \over {15}}

=23 ⋅ 240015= {{{2^3}\, \cdot \,{2^{400}}} \over {15}}

=815(16)100= {8 \over {15}}{\left( {16} \right)^{100}}

=815(15+1)100= {8 \over {15}}{\left( {15 + 1} \right)^{100}}

=815(100C0+100C1 15+100C2(15)2+.....(15)100)= {8 \over {15}}\left( {{}^{100}{C_0} + {}^{100}{C_1}\,15 + {}^{100}{C_2}{{\left( {15} \right)}^2} + .....{{\left( {15} \right)}^{100}}} \right)

=815+8(100C1+100C2 (15)+.....+(15)99)= {8 \over {15}} + 8\left( {{}^{100}{C_1} + {}^{100}{C_2}\,\left( {15} \right) + ..... + {{\left( {15} \right)}^{99}}} \right)

=815+8= {8 \over {15}} + 8 (integer)

∴\therefore   Fractional part =815= {8 \over {15}}

According to the question,

k15=815{k \over {15}} = {8 \over {15}}

⇒\Rightarrow    K == 8

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