QJEEM19Chf966: JEE Main 2019 Chemistry - Class 12 JEEM19Chf966 Solution: In the following reaction; xA yB 'A' and 'B' respectively can…

Question

Verified Solution • 2025–26 Session moderate

In the following reaction; xA

\to

yB

{\log _{10}}\left[ { - {{d\left[ A \right]} \over {dt}}} \right] = {\log _{10}}\left[ {{{d\left[ B \right]} \over {dt}}} \right] + 0.3010

'A' and 'B' respectively can be :

Accepted Answer

xA

\to

yB

{1 \over x}\left\{ { - {{d\left[ A \right]} \over {dt}}} \right\} = {1 \over y}\left\{ {{{d\left[ B \right]} \over {dt}}} \right\}

\Rightarrow

- {{d\left[ A \right]} \over {dt}} = {x \over y}\left\{ {{{d\left[ B \right]} \over {dt}}} \right\}

Taking log both sides, we get

\Rightarrow

{\log _{10}}\left[ { - {{d\left[ A \right]} \over {dt}}} \right] = {\log _{10}}\left[ {{{d\left[ B \right]} \over {dt}}} \right] + {\log _{10}}\left( {{x \over y}} \right)

Given that,

{\log _{10}}\left[ { - {{d\left[ A \right]} \over {dt}}} \right] = {\log _{10}}\left[ {{{d\left[ B \right]} \over {dt}}} \right] + 0.3010

So, by comparing both of them we get

{\log _{10}}\left( {{x \over y}} \right)

= 0.3010 =

{\log _{10}}\left( 2 \right)

\therefore

{{x \over y}}

= 2

\Rightarrow

x = 2y

If x = 2 then y = 1

The reaction is of type 2A

\to

B

So possible reaction is

2C₂H₄

\to

C₄H₈

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