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QJEEM19Chf945: JEE Main 2019 Chemistry - Class 11 JEEM19Chf945 Solution: The hardness of a water sample (in terms of equivalents of CaCO …

The hardness of a water sample (in terms of equivalents of CaCO3) containing 10–3 M CaSO4 is (Molar mass of CaSO4 = 136 g mol–1)

Multiple Choice Options

  • A 90 ppm
  • B 100 ppm
  • C 50 ppm
  • D 10 ppm

Step-by-Step Verified Solution

nCaSO4 × Van't hoff factor = nCaCO3 × Van't hoff factor

⇒ 10-3 × 2 = nCaCO3 × 2

⇒ nCaCO3 = 10-3 mol in 1 L

∴ wCaCO3 = 100 × 10-3 g CaCO3 in 1 L solution

∴ hardness in terms of CaCO3

= wCaCO3wTotal×106

= 100×10−31000×106

= 100 ppm

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