QJEEM19Chf4a4: JEE Main 2019 Chemistry - Class 12 JEEM19Chf4a4 Solution: Hall- Heroult's process is given by :

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QJEEM19Chf4a4: JEE Main 2019 Chemistry - Class 12 JEEM19Chf4a4 Solution: Hall- Heroult's process is given by :

Hall- Heroult's process is given by :

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A Cu2+ (aq) + H2(g) $\to$ Cu(s) + 2H+ (aq)
B Cr2O3 + 2AI $\to$ Al2O3 + 2Cr
C 2Al2O3 + 3C $\to$ 4Al + 3CO2
D ZnO + C ⟶Coke,1673K Zn + CO

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Accepted Answer

In Hall-Heroult's process is given by
JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Isolation of Elements Question 99 English Explanation

JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Isolation of Elements Question 99 English Explanation

At cathode :-

4 A l_{(ℓ)}^{3 +} + 12 e^{-} \underset{}{⟶} 4 A l (ℓ)

At Anode :-

6 O_{(ℓ)}^{2 -} \underset{}{⟶} 3 O_{2} (g) + 12 e^{-}

3 C + 3 O_{2} \underset{}{⟶} 3 C O_{2} (↑)

QJEEM19Chf4a4: JEE Main 2019 Chemistry - Class 12 JEEM19Chf4a4 Solution: Hall- Heroult's process is given by :

Multiple Choice Options

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