QJEEM19Che7c3: JEE Main 2019 Chemistry - Class 11 JEEM19Che7c3 Solution: For the following reactions, equilibrium constants are given :…

S(s) + O₂(g) ⇋ SO₂(g); K₁ = 10⁵²

By reversing the equation, we get

SO₂(g); ⇋ S(s) + O₂(g) ; $$\frac{1}{K_1}=\frac{1}{{10}^{52}}$$ ..............(1)

2S(s) + 3O₂(g) ⇋ 2SO₃(g); K₂ = 10¹²⁹ ....................(2)

Performing (2) - 2 $$\times$$ (1), we get

2SO₂(g) + O₂(g) ⇋ 2SO₃(g)

$$\therefore$$ Equilibrium constant of this reaction is

= $$\frac{K_2}{K_1^2}$$ = $$\frac{{10}^{129}}{{\left({10}^{52}\right)}^2}$$ = 10²⁵