Verified Solution • 2025–26 Session moderate

QJEEM19Chd1c6: JEE Main 2019 Chemistry - Class 11 JEEM19Chd1c6 Solution: A mixture of 100 m mol of Ca(OH) 2 and 2 g of sodium sulphate…

A mixture of 100 m mol of Ca(OH)2 and 2 g of sodium sulphate was dissolved in water and the volume was made up to 100 mL. The mass of calcium sulphate formed and the concentration of OH– in resulting solution, respectively, are : (Molar mass of Ca (OH)2, Na2SO4 and CaSO4 are 74, 143 and 136 g mol–1 , respectively; Ksp of Ca(OH)2 is 5.5 × 10–6 )

Multiple Choice Options

  • A 13.6g, 0.28 mol L −- 1
  • B 13.6g, 0.14 mol L −- 1
  • C 1.9g, 0.28 mol L −- 1
  • D 1.9g, 0.14 mol L −- 1

Step-by-Step Verified Solution

Ca(OH)2 + Na2SO4 →\to CaSO4 + 2NaOH

100 m mol 14 m mol       −-       −-        −-

−-      −-        −-   14 m mol 28 m mol

wCasO4 = 14 ×\times 10 −- 3 ×\times 136 = 1.9 gm

[OH −- ] = 28100{{28} \over {100}} = 0.28 M

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