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QJEEM19Chce42: JEE Main 2019 Chemistry - Class 11 JEEM19Chce42 Solution: Two solids dissociate as follows – The total pressure when both …

Two solids dissociate as follows –
JEE Main 2019 (Online) 12th January Morning Slot Chemistry - Chemical Equilibrium Question 73 English
The total pressure when both the solids dissociated simultaneously is -

Multiple Choice Options

  • A (x + y) atm
  • B (x+y)\left( {\sqrt {x + y} } \right) atm
  • C 2 (x+y)\left( {\sqrt {x + y} } \right) atm
  • D x2 + y2 atm

Step-by-Step Verified Solution

JEE Main 2019 (Online) 12th January Morning Slot Chemistry - Chemical Equilibrium Question 73 English Explanation

Kp1 = P1(P1 + P2)

Kp2 = P2(P1 + P2)

∴\therefore Kp1 + Kp2 = (P1 + P2)2

⇒\Rightarrow x + y = (P1 + P2)2

⇒\Rightarrow (P1 + P2) = x+y\sqrt {x + y} .....(1)

Now total pressure

PT = PC + PB + PE

= (P1 + P2) + P1 + P2

= 2(P1 + P2)

= 2x+y2\sqrt {x + y}     [From equation (1)]

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