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QJEEM19Chc964: JEE Main 2019 Chemistry - Class 12 JEEM19Chc964 Solution: K 2 Hgl 4 is 40% ionised in aqueous solution. The value of its…

K2Hgl4 is 40% ionised in aqueous solution. The value of its van't Hoff factor (i) is:

Multiple Choice Options

  • A 1.6
  • B 2.2
  • C 2
  • D 1.8

Step-by-Step Verified Solution

K2Hgl4 is 40% ionised.

∴\therefore α\alpha = 40100{{40} \over {100}} = 0.4

K2[Hgl4] →\to 2K+ + [Hgl4]2+

N = 2+11{{2 + 1} \over 1} = 3

i = 1 + (N - 1) α\alpha

= 1 + (3 - 1)0.4

= 1 + 2 ×\times 0.4

= 1.8

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