Verified Solution • 2025–26 Session moderate

QJEEM19Chc620: JEE Main 2019 Chemistry - Class 11 JEEM19Chc620 Solution: If solublity product of Zr 3 (PO 4 ) 4 is denoted by K sp and…

If solublity product of Zr3(PO4)4 is denoted by Ksp and its molar solubility is denoted by S, then which of the following relation between S and Ksp is correct ?

Multiple Choice Options

  • A S=(Ksp929)1/9S = {\left( {{{{K_{sp}}} \over {929}}} \right)^{1/9}}
  • B S=(Ksp6912)1/7S = {\left( {{{{K_{sp}}} \over {6912}}} \right)^{1/7}}
  • C S=(Ksp144)1/6S = {\left( {{{{K_{sp}}} \over {144}}} \right)^{1/6}}
  • D S=(Ksp216)1/7S = {\left( {{{{K_{sp}}} \over {216}}} \right)^{1/7}}

Step-by-Step Verified Solution

Zr3(PO4)4 ⇌ 3Zr+4 + 4PO4-3
S 3S 4S


Ksp = [Zr+4]3 [PO4-3]4

= [3S]3 [4S]4

= 27S3 ×\times 256S4

= 6912S7

∴\therefore S=(Ksp6912)1/7S = {\left( {{{{K_{sp}}} \over {6912}}} \right)^{1/7}}

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