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QJEEM19Chc4aa: JEE Main 2019 Chemistry - Class 11 JEEM19Chc4aa Solution: In order to oxidise a mixture of one mole of each of FeC 2 O 4…

In order to oxidise a mixture of one mole of each of FeC2O4, Fe2(C2O4)3, FeSO4 and Fe2(SO4)3 in acidic medium, the number of moles of KMnO4 required is :

Multiple Choice Options

  • A 1.5
  • B 3
  • C 2
  • D 1

Step-by-Step Verified Solution

JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Redox Reactions Question 56 English Explanation

∴\therefore Equivalent of KMnO4 = Eq of FeC2O4 + Eq of Fe2(C2O4)3 + FeSO4

⇒\Rightarrow moles of KMnO4 ×\times 5 = 3 ×\times 1 + 6 ×\times 1 + 1 ×\times 1

⇒\Rightarrow moles of KMnO4 = 105{{10} \over 5} = 2

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