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QJEEM19Chbb45: JEE Main 2019 Chemistry - Class 11 JEEM19Chbb45 Solution: During the change of O 2 to O 2 - , the incoming electron goes…

During the change of O2 to O2- , the incoming electron goes to the orbital :

Multiple Choice Options

  • A π2py\pi 2{p_y}
  • B σ∗2pz{\sigma ^*}2{p_z}
  • C π∗2px{\pi ^*}2{p_x}
  • D π2px\pi 2{p_x}

Step-by-Step Verified Solution

Molecular orbital configuration of O2 (16 electrons) is

σ1s2 σ1s2∗ σ2s2 σ2s2∗ σ2pz2 π2px2 = π2py2 π2px1∗ = π2py1∗{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\sigma _{2p_z^2}}\,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,\pi _{2p_x^1}^ * \, = \,\pi _{2p_y^1}^ *

Molecular orbital configuration of O2- (17 electrons) is

σ1s2 σ1s2∗ σ2s2 σ2s2∗ σ2pz2 π2px2 = π2py2 π2px2∗ = π2py1∗{\sigma _{1{s^2}}}\,\sigma _{1{s^2}}^ * \,{\sigma _{2{s^2}}}\,\sigma _{2{s^2}}^ * \,{\sigma _{2p_z^2}}\,{\pi _{2p_x^2}}\, = \,{\pi _{2p_y^2}}\,\pi _{2p_x^2}^ * \, = \,\pi _{2p_y^1}^ *

So, the incoming electron goes to π2px∗\pi _{2p_x}^ * or π2py∗\pi _{2p_y}^ *

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