Verified Solution • 2025–26 Session moderate

QJEEM19Chb767: JEE Main 2019 Chemistry - Class 11 JEEM19Chb767 Solution: Given (i)  C (graphite) + O 2 (g) CO 2 (g); rH = x kJ …

Given

(i)  C (graphite) + O2(g) →\to CO2(g); Δ\Delta rH Θ^\Theta = x kJ mol −- 1

(ii)  C(graphite) + 12{1 \over 2} O2(g) →\to CO(g); Δ\Delta rH Θ^\Theta = y kJ mol −- 1

(iii)  CO(g) + 12{1 \over 2} O2(g) →\to CO2(g); Δ\Delta rH Θ^\Theta = z kJ mol −- 1

Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?

Multiple Choice Options

  • A z = x + y
  • B x = y + z
  • C x = y – z
  • D y = 2z – x

Step-by-Step Verified Solution

In reaction (i), the product is CO2

If we add reaction (ii) and (iii) we get,
      C + O2   →\to  CO2
here also product is CO2 from same reactant C and O2.

So according to hess law, we can say
      x = y + z

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