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QJEEM19Chb6e5: JEE Main 2019 Chemistry - Class 12 JEEM19Chb6e5 Solution: A solution of Ni(NO 3 ) 2 is electrolysed between platinum…
A solution of Ni(NO3)2 is electrolysed between platinum electrodes using 0.1 Faraday electricity. How many mole of Ni will be deposited at the cathode?
Multiple Choice Options
- A 0.1
- B 0.15
- C 0.2
- D 0.05
Step-by-Step Verified Solution
Cathode reaction :
Ni+2 + 2e- Ni(s)
From 2 mole of electrons 1 mole of Ni is deposited at the cathode.
So from 0.1 F or 0.1 mole of electrons = 0.05 mole of Ni is deposited at the cathode.
Ni+2 + 2e- Ni(s)
From 2 mole of electrons 1 mole of Ni is deposited at the cathode.
So from 0.1 F or 0.1 mole of electrons = 0.05 mole of Ni is deposited at the cathode.