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QJEEM19Chb5ac: JEE Main 2019 Chemistry - Class 11 JEEM19Chb5ac Solution: An organic compound 'A' is oxidizod with Na 2 O 2 followed by…

An organic compound 'A' is oxidizod with Na2O2 followed by boiling with HNO3. The resultant solution is then treated with ammonium molybdate to yield a yellow precipitate.
Based on above observation, the element present in the given compound is:

Multiple Choice Options

  • A Fluorine
  • B Phosphorus
  • C Nitrogen
  • D Sulphur

Step-by-Step Verified Solution

Phosphorus is detected in the form of canary yellow ppt on reaction with ammonium molybdate. JEE Main 2019 (Online) 12th April Morning Slot Chemistry - Practical Organic Chemistry Question 68 English Explanation

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