Verified Solution • 2025–26 Session
moderate
QJEEM19Chb503: JEE Main 2019 Chemistry - Class 11 JEEM19Chb503 Solution: 5 moles of an ideal gas at 100 K are allowed to undergo…
5 moles of an ideal gas at 100 K are allowed to undergo reversible compression till its temperature becomes 200 K. If CV = 28 JK–1mol–1, calculate U and pV for this process. (R = 8.0 JK–1 mol–1]
Multiple Choice Options
- A U = 14 kJ; (pV) = 4 kJ
- B U = 2.8 kJ; (pV) = 0.8 kJ
- C U = 14 kJ; (pV) = 18 kJ
- D U = 14 kJ; (pV) = 0.8 kJ
Step-by-Step Verified Solution
For ideal gas,
U = nCv T
= 5 28 (200 - 100)
= 14 kJ
We know,
PV = nRT
(PV) = nR T = 5 8 100 = 4 kJ
U = nCv T
= 5 28 (200 - 100)
= 14 kJ
We know,
PV = nRT
(PV) = nR T = 5 8 100 = 4 kJ