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QJEEM19Cha1c2: JEE Main 2019 Chemistry - Class 11 JEEM19Cha1c2 Solution: During compression of a spring the work done is 10kJ and 2kJ…
During compression of a spring the work done is 10kJ and 2kJ escaped to the surroundings as heat. The change in internal energy, U(inkJ) is :
Multiple Choice Options
- A -12
- B 8
- C -8
- D 12
Step-by-Step Verified Solution
Here heat is released so q is negative.
q = - 2 kJ
Work done on the system, w = 10 kJ
From first law of thermodynamics,
U = q + w = -2 + 10 = 8 kJ
q = - 2 kJ
Work done on the system, w = 10 kJ
From first law of thermodynamics,
U = q + w = -2 + 10 = 8 kJ