Verified Solution • 2025–26 Session moderate

QJEEM19Ch9b64: JEE Main 2019 Chemistry - Class 11 JEEM19Ch9b64 Solution: The INCORRECT match in the following is :

The INCORRECT match in the following is :

Multiple Choice Options

  • A Δ\Delta Go = 0, K = 1
  • B Δ\Delta Go < 0, K < 1
  • C Δ\Delta Go > 0, K < 1
  • D Δ\Delta Go < 0, K > 1

Step-by-Step Verified Solution

We know, ΔGo=−RTln⁡K\Delta {G^o} = - RT\ln K
Case 1 :
If Δ\Delta Go < 0
⇒\Rightarrow −RTln⁡K- RT\ln K < 0
⇒\Rightarrow ln⁡K\ln K > 0
⇒\Rightarrow K > 1

Case 2 :
If Δ\Delta Go > 0
⇒\Rightarrow −RTln⁡K- RT\ln K > 0
⇒\Rightarrow ln⁡K\ln K < 0
⇒\Rightarrow K < 1

Case 2 :
If Δ\Delta Go = 0
⇒\Rightarrow −RTln⁡K- RT\ln K = 0
⇒\Rightarrow ln⁡K\ln K = 0
⇒\Rightarrow K = 1

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