Verified Solution • 2025–26 Session moderate

QJEEM19Ch8dc0: JEE Main 2019 Chemistry - Class 11 JEEM19Ch8dc0 Solution: An open vessel at 27 o C is heated until two fifth of the air…

An open vessel at 27oC is heated until two fifth of the air (assumed as an ideal gas) it has escaped from the vessel assuming that the volume of the vessel remains constant, the temperature at which the vessel has been heated is -

Multiple Choice Options

  • A 750 K
  • B 500oC
  • C 750oC
  • D 500 K

Step-by-Step Verified Solution

We know,

PV = nRT

As the vessel is open, so the pressure and volume is constant.

∴\therefore    n1 R T1 = n2 R T2

⇒\Rightarrow    n1 T1 = n2 T1

25{2 \over 5} th of the air escape from the vessel. So the remaining air is 35{3 \over 5} of the total air.

∴\therefore    n ×\times 300 = 35{3 \over 5} n ×\times T2

⇒\Rightarrow    T2 = 500 K

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