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QJEEM19Ch8b68: JEE Main 2019 Chemistry - Class 11 JEEM19Ch8b68 Solution: The volume of gas A is twice than that of gas B. The…

The volume of gas A is twice than that of gas B. The compressibility factor of gas A is thrice than that of gas B at same temperature. The pressures of the gases for equal number of moles are -

Multiple Choice Options

  • A 2PA = 3PB
  • B 3PA = 2PB
  • C PA = 3PB
  • D PA = 2PB

Step-by-Step Verified Solution

Z = PV/nRT

⇒ P = ZnRTV

at constant T and mol(n),

P ∝ ZV

⇒ PAPB=ZAZA×VBVA

= (31)×(12) = 32

∴ 2PA = 3PB

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