Verified Solution • 2025–26 Session
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QJEEM19Ch864d: JEE Main 2019 Chemistry - Class 11 JEEM19Ch864d Solution: The lathanide ion that would show colour is :
The lathanide ion that would show colour is :
Multiple Choice Options
- A Sm3+
- B Gd3+
- C Lu3+
- D La3+
Step-by-Step Verified Solution
Electronic configuration of
Sm = [Xe] 4f6 6s2
Sm+3 = [Xe] 4f5
Sm+3 shows yellow colour due to partially filled f orbital and f-f transition.
Electronic configuration of
La+3 = [Xe] 4f0
Lu+3 = [Xe] 4f14
Gd+3 = [Xe] 4f7
La+3, Lu+3 and Gd+3 are colourless due to absence of f-f transition.
Sm = [Xe] 4f6 6s2
Sm+3 = [Xe] 4f5
Sm+3 shows yellow colour due to partially filled f orbital and f-f transition.
Electronic configuration of
La+3 = [Xe] 4f0
Lu+3 = [Xe] 4f14
Gd+3 = [Xe] 4f7
La+3, Lu+3 and Gd+3 are colourless due to absence of f-f transition.