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QJEEM19Ch85c1: JEE Main 2019 Chemistry - Class 11 JEEM19Ch85c1 Solution: The type of hybridisation and number of lone pair (s) of…
The type of hybridisation and number of lone pair (s) of electrons of Xe in XeOF4, respectively, are:
Multiple Choice Options
- A sp3d and 2
- B sp3d2 and 2
- C sp3d and 1
- D sp3d2 and 1
Step-by-Step Verified Solution
H = (V + M - c + a)
H = (8 + 4) = 6
From structure, it is clear that it has five bond pairs and one lone pair.
From structure, it is clear that it has five bond pairs and one lone pair.