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QJEEM19Ch85c1: JEE Main 2019 Chemistry - Class 11 JEEM19Ch85c1 Solution: The type of hybridisation and number of lone pair (s) of…

The type of hybridisation and number of lone pair (s) of electrons of Xe in XeOF4, respectively, are:

Multiple Choice Options

  • A sp3d and 2
  • B sp3d2 and 2
  • C sp3d and 1
  • D sp3d2 and 1

Step-by-Step Verified Solution

H = 12 (V + M - c + a)

∴ H = 12(8 + 4) = 6
JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Chemical Bonding & Molecular Structure Question 180 English Explanation

From structure, it is clear that it has five bond pairs and one lone pair.

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