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QJEEM19Ch7fd1: JEE Main 2019 Chemistry - Class 12 JEEM19Ch7fd1 Solution: Consider the given plots for a reaction obeying Arrhenius…

Consider the given plots for a reaction obeying Arrhenius equation (0oC < T < 300oC) : (K and Ea are rate constant and activation energy, respectively)

JEE Main 2019 (Online) 10th January Morning Slot Chemistry - Chemical Kinetics and Nuclear Chemistry Question 135 English

Choose the correct option :

Multiple Choice Options

  • A I is right but II is wrong
  • B Both I and II are correct
  • C Both I and II are wrong
  • D I is wrong but II is right

Step-by-Step Verified Solution

Arrhenius Equation -

Arrhenius gave the quantitative dependence of rate constant on temperature by the Arrhenius equation.

- wherein

k=Ae−Ea/RTk = A{e^{ - {E_a}/RT}}

lnk=lnA−EaRT{\mathop{\rm lnk}\nolimits} = lnA - {{{E_a}} \over {RT}}

k = Rate constant

as we have learned in Arrhenius equation when we increase Ea, K should decrease As T increases, power of exponential increases so k also increase.

Hence, both the plots are correct.

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