QJEEM19Ch7a40: JEE Main 2019 Chemistry - Class 11 JEEM19Ch7a40 Solution: For emission line of atomic hydrogen from n i = 8 to n f = n,…

Question

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For emission line of atomic hydrogen from n_i = 8 to n_f = n, the plot of wave number

\left( {\overline v } \right)

against

\left( {{1 \over {{n^2}}}} \right)

will be (The Rydberg constant, R_H is in wave number unit)

Accepted Answer

We know,

\overline v = {1 \over \lambda } = {R_H}{Z^2}\left[ {{1 \over {n_f^2}} - {1 \over {n_i^2}}} \right]

here n_i

=

8 and n_f

=

n

Z

=

1 for hydrogen

\therefore

\overline v = {1 \over \lambda } = {R_H}\left[ {{1 \over {{n^2}}} - {1 \over {{8^2}}}} \right]

So, graph is

\to

So, graph will be linear with slope R_H.

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