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QJEEM19Ch6d26: JEE Main 2019 Chemistry - Class 11 JEEM19Ch6d26 Solution: For the following reaction, in the mass of water produced from…

For the following reaction, in the mass of water produced from 445 g of C57H110O6 is :

2C57H110O6(s) + 163 O2(g) → 114 CO2(g) + 110 H2O(l)

Multiple Choice Options

  • A 490 g
  • B 445 g
  • C 495 g
  • D 890 g

Step-by-Step Verified Solution

moles of C57H110O6(s) = 445890 = 0.5 moles

2C57H110O6(s) + 163 O2(g) → 114 CO2(g) + 110 H2O(l)

nH2O = 1104 = 552

mH2O = 552 × 18

= 495 gm

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