QJEEM19Ch6cef: JEE Main 2019 Chemistry - Class 12 JEEM19Ch6cef Solution: The given plots represent the variation of the concentration of …

For 1^st order reaction, we know

$$\ln \frac{R_0}{R_T}=kt$$

$$\Rightarrow$$ $$\ln R_0$$ - $$\ln R_t$$ = kt

$$\Rightarrow$$ $$\ln R_t$$ = - kt + $$\ln R_0$$

So, $$\ln R_t$$ vs t is a straight line with negative slope.

$$\therefore$$ First graph represent 1^st order reaction.

For Zeroorder reaction, we know

R₀ - R_t = kt

$$\therefore$$ R_t = - kt + R₀

So, $$R_t$$ vs t is a straight line with negative slope.

$$\therefore$$ Second graph represent zero order reaction.