Verified Solution • 2025–26 Session moderate

QJEEM19Ch695e: JEE Main 2019 Chemistry - Class 12 JEEM19Ch695e Solution: For the solution of the gases w, x, y and z in water at 298K,…

For the solution of the gases w, x, y and z in water at 298K, the Henrys law constants (KH) are 0.5, 2, 35 and 40 kbar, respectively. The correct plot for the given data is :-

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/a8dffbf30d93e0144ae34067a13f2b221202b78a5b03ffccf73108d2af3feb14.webp
  • B https://ik.imagekit.io/novatra/photos/0ceaea599a75fa8bd80c149e111541553aede362054ec79bb29cbff367951b7e.webp
  • C https://ik.imagekit.io/novatra/photos/5f3f0339b86acce6f9ebcd39268d0353e708c1b3bd33f29e6eaf0060d0777320.webp
  • D https://ik.imagekit.io/novatra/photos/f5bb3e6b514609aea105f8d27de5972e32956cadca619a931e92999769b706e8.webp

Step-by-Step Verified Solution

Henry's law expression,

Pgas = KH ×\times xgas

Here, Pgas = partial pressure of gas

KH = Henry’s law constant

xgas = mole fraction of gas

∵\because xgas = 1 - xH2O

∴\therefore Pgas = KH ×\times (1 - xH2O)

⇒\Rightarrow Pgas = KH - KH ×\times xH2O

By comparing this equation with y = mx + c,

c = KH = Intercept

m = - KH = slope

So in partial pressure vs mole fraction of water graph, which gas has more KH will have more intercept. Given (KH) are 0.5, 2, 35 and 40 kbar for w, x, y, z respectively. So intercept of z should be the most and should be the least.

As solpe is = - KH, so slope shoul be negative for all the gases and w gas should have least negative slope and z should have highest negative slope.

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring