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QJEEM19Ch6450: JEE Main 2019 Chemistry - Class 11 JEEM19Ch6450 Solution: At a given temperature T, gases Ne, Ar, Xe and Kr are found to…

At a given temperature T, gases Ne, Ar, Xe and Kr are found to deviate from ideal gas behaviour. Their equation of state is given as

p=RTV−b at T.

Here, b is the van der Waals constant. Which gas will exhibit steepest increase in the plot of Z (compression factor) vs p?

Multiple Choice Options

  • A Xe
  • B Ne
  • C Ar
  • D Kr

Step-by-Step Verified Solution

Given p=RTV−b

⇒ p(V−b)=RT

⇒ pVRT=pbRT+RTRT

⇒ Z = bRTp+1

∴ Slope of Z vs p curve (straight line) = bRT

∴ Higher the value of b, more steep will be the curve.

As we know, b = 4vNA = 4×43πr3×NA

∴ b ∝ size of gas molecules

Among Ne, Ar, Xe and Kr, size of Xe is the most as down the group in the periodic table size increases.

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