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QJEEM19Ch63e1: JEE Main 2019 Chemistry - Class 12 JEEM19Ch63e1 Solution: p-Hydroxybenzophenone upon reaction with bromine in carbon…

p-Hydroxybenzophenone upon reaction with bromine in carbon tetrachloride gives:

Multiple Choice Options

  • A https://ik.imagekit.io/novatra/photos/a010c0902223476dbc31e50dd955a16b76f3c3cfab1b37b91c50fe82855af09d.webp
  • B https://ik.imagekit.io/novatra/photos/252c8a97278d5ace5d1d9d6afefd56411c97d1b14d24d2e03b33e055c8f97687.webp
  • C https://ik.imagekit.io/novatra/photos/14e12b919f0f30d71fd11a6d4aeefefd945538b456cc1eed506c6898f62e4ea7.webp
  • D https://ik.imagekit.io/novatra/photos/e2847b134ee11f75ff919e0c1ce86957edf1948b841f0675d1938555c2e97d4b.webp

Step-by-Step Verified Solution

JEE Main 2019 (Online) 9th April Evening Slot Chemistry - Aldehydes, Ketones and Carboxylic Acids Question 177 English Explanation

-OH is +M group which will activate the corresponding benzene ring and -C(=O)- is -M group which will deactivate the right benzene ring completely. So Br+ electrophyle will attack electron rich position, which is ortho or para position of -OH group but you can see para position is blocked by -C(=O)- group so Br+ will attack any of the ortho position of -OH group.

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