QJEEM19Ch5553: JEE Main 2019 Chemistry - Class 11 JEEM19Ch5553 Solution: The ground state energy of hydrogen atom is – 13.6 eV. The…

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The ground state energy of hydrogen atom is – 13.6 eV. The energy of second excited state of He⁺ ion in eV is :

Accepted Answer

(E)_n^th = (E_GND)_H .

{{{Z^2}} \over {{n^2}}}

E_3^rd (He⁺) = (

-

13.6eV) .

{{{2^2}} \over {{3^2}}}

=

-

6.04 eV

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