Verified Solution • 2025–26 Session moderate

QJEEM19Ch3c97: JEE Main 2019 Chemistry - Class 11 JEEM19Ch3c97 Solution: The molar solubility of Cd(OH) 2 is 1.84 × 10 –5 M in water.…

The molar solubility of Cd(OH)2 is 1.84 × 10–5 M in water. The expected solubility of Cd(OH)2 in a buffer solution of pH = 12 is :

Multiple Choice Options

  • A 2.49 × 10–10 M
  • B 1.84 × 10–9 M
  • C 6.23 × 10–11 M
  • D 2.491.84×10−9M

Step-by-Step Verified Solution

Cd(OH)2(s) ⇌ Cd2+(aq) + 2OH−(aq)
S 2S

∴ Ksp[Cd(OH)2] = 4(S)3 = 4(1.84 × 10–5)3 [Given S = 1.84 × 10–5]

For buffer solution of pH = 12 :
As pH = 12 so pOH = 2
⇒ [OH−] = 10-2
Let the solubilty = S1

Cd(OH)2(s) ⇌ Cd2+(aq) + 2OH−(aq)
S1 2S1 + 10-2

∴ Ksp[Cd(OH)2] = S1(10-2)2 = 4(1.84 × 10–5)3
⇒ S1 = 2.49 × 10–10 M

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