QJEEM19Ch3813: JEE Main 2019 Chemistry - Class 11 JEEM19Ch3813 Solution: What is the molar solubility of Al(OH) 3 in 0.2 M NaOH solution …

Question

Verified Solution • 2025–26 Session moderate

What is the molar solubility of Al(OH)₃ in 0.2 M NaOH solution ? Given that, solubility product of Al(OH)₃ = 2.4 × 10^–24 :

Accepted Answer

K_{s p} =

[Al³⁺][OH^-]³

\Rightarrow

2.4 × 10^–24 = s(0.2)³

\Rightarrow

s =

\frac{2.4 \times 10^{- 24}}{8 \times 10^{- 3}}

\Rightarrow

s = 3 × 10^–22

Step-by-Step Verified Solution