Verified Solution • 2025–26 Session moderate

QJEEM19Ch28fd: JEE Main 2019 Chemistry - Class 12 JEEM19Ch28fd Solution: The coordination number of Th in K 4 [Th(C 2 O 4 ) 4 (OH 2 ) 2…

The coordination number of Th in K4[Th(C2O4)4(OH2)2] is :
(C2O 42−{_4^{2 - }} = Oxalato)

Multiple Choice Options

  • A 14
  • B 10
  • C 8
  • D 6

Step-by-Step Verified Solution

Oxalato (C2O42–) is a bidentate and H2O is unidentate ligand.

4C2O42– creates 8 covalent bonds.

2H2O creates 2 covalent bonds.

∴\therefore Around Th 10 coordinate covalent bonds will be present.

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