QJEEM19Ch2016: JEE Main 2019 Chemistry - Class 11 JEEM19Ch2016 Solution: The graph between and r (radial distance) is shown below. This…

In this ${\left| \psi \right|^2}$ vs r graph, value of r is zero at only one point. So this orbital must have one radial node.

Here ${\left| \psi \right|^2} \ne 0$ at r = 0, so orbital should be s orbital. Then $l$ = 0.

We know,

No of radial node = n - $l$ - 1

$\therefore$ n - $l$ - 1 = 1

$\Rightarrow$ n - 0 - 1 = 1

$\Rightarrow$ n = 2

Therefore orbital is 2s.