Verified Solution • 2025–26 Session moderate

QJEEM19Ch17e0: JEE Main 2019 Chemistry - Class 11 JEEM19Ch17e0 Solution: If the de Broglie wavelength of the electron in n th Bohr orbit …

If the de Broglie wavelength of the electron in nth Bohr orbit in a hydrogenic atom is equal to 1.5 π\pi a0 (a0 is Bohr radius), then the value of n/z is -

Multiple Choice Options

  • A 0.75
  • B 0.4
  • C 1.5
  • D 1

Step-by-Step Verified Solution

According to debroglie hypothesis,

2 π\pi rn = n λ\lambda

∴\therefore    λ\lambda = 2πrnn{{2\pi {r_n}} \over n}

According to the question,

2πrnn{{2\pi {r_n}} \over n} = 1.5 π\pi a0

We know,

rn = 0.529 n2Z{{{n^2}} \over Z}

    = a0 ×\times n2Z{{{n^2}} \over Z}

∴\therefore    2πn×a0n2Z{{2\pi } \over n} \times {{{a_0}{n^2}} \over Z} = 1.5 π\pi a0

⇒\Rightarrow    nZ{n \over Z} = 0.75

Related Learning Resources & Exam Preparation