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QJEEM19Ch161b: JEE Main 2019 Chemistry - Class 11 JEEM19Ch161b Solution: The increasing basicity order of the following compounds is :
The increasing basicity order of the following compounds is :
Multiple Choice Options
- A A < B < D < C
- B D < C < A < B
- C D < C < B < A
- D A < B < C < D
Step-by-Step Verified Solution
(A) In the first compound, because of +I effect of CH3CH2- group electron density increses on N atom.
(B) In the second compound, because of +I effect of two CH3CH2- group electron density is more on N atom than first compound so it is more basic than compound A.
(C) Three -CH3 group creates steric hindrance around N atom, for that reason N atom can't donate lone pair easily.
(D) Here lone pair of N atom, perticipate in resonance with benzene ring so N atom can't donate lone pair. That is why it is least basic among this four compounds.
So correct order is D < C < A < B.
(B) In the second compound, because of +I effect of two CH3CH2- group electron density is more on N atom than first compound so it is more basic than compound A.
(C) Three -CH3 group creates steric hindrance around N atom, for that reason N atom can't donate lone pair easily.
(D) Here lone pair of N atom, perticipate in resonance with benzene ring so N atom can't donate lone pair. That is why it is least basic among this four compounds.
So correct order is D < C < A < B.