QJEEM19Ch0fc6: JEE Main 2019 Chemistry - Class 11 JEEM19Ch0fc6 Solution: For a reaction, N 2 (g) + 3H 2 (g) 2NH 3 (g) ; identify…

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N₂(g) + 3H₂(g) $\to$ 2NH₃(g)

For dihydrogen (H₂) to become a limiting reagent,

${{moles\,of\,{H_2}} \over {stoichiometric\,coefficient\,of\,{H_2}}}$ should be

less than ${{moles\,of\,{N_2}} \over {stoichiometric\,coefficient\,of\,{N_2}}}$ .

Here in 56g of N₂ + 10g of H₂,

Moles of N₂ = ${{56} \over {28}}$ = 2

and Moles of H₂ = ${{10} \over 2}$ = 5

Now by dividing stoichiometric coefficient we get,

For N₂ = ${2 \over 1}$ = 2

For H₂ = ${5 \over 3}$ = 1.67

$\therefore$ Here H₂ is the limiting reagent.