Verified Solution • 2025–26 Session moderate

QJEEM19Ch0e22: JEE Main 2019 Chemistry - Class 12 JEEM19Ch0e22 Solution: For the reaction of H 2 with I 2 , the rate constant is 2.5 ×…

For the reaction of H2 with I2, the rate constant is 2.5 × 10–4 dm3 mol–1s–1 at 327°C and 1.0 dm3 mol–1 at 527°C. The activation energy for the reaction, in kJ mole–1 is : (R = 8.314 JK–1 mol–1 )

Multiple Choice Options

  • A 59
  • B 166
  • C 72
  • D 150

Step-by-Step Verified Solution

From Arrhenius equation, we get

log⁡K2K1=Ea2.303R(1T1−1T2)

⇒ log⁡12.5×10−4=Ea2.303×8.314(1600−1800)

⇒ 3.6 = Ea2.303×8.314×200600×800

⇒ Ea = 166 kJ/mol

Related Learning Resources & Exam Preparation

JEE Main PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring