Verified Solution • 2025–26 Session moderate

QJEEM19Ch0d04: JEE Main 2019 Chemistry - Class 12 JEEM19Ch0d04 Solution: 1 g of a non-volatile non-electrolyte solute is dissolved in…

1 g of a non-volatile non-electrolyte solute is dissolved in 100 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1 : 5. The ratio of the elevation in their boiling points, ΔTb(A)ΔTb(B){{\Delta {T_b}(A)} \over {\Delta {T_b}(B)}} , is :

Multiple Choice Options

  • A 5:01
  • B 01:00.2
  • C 10:01
  • D 1:05

Step-by-Step Verified Solution

Given,

(kb)A(kb)B=15{{{{\left( {{k_b}} \right)}_A}} \over {{{\left( {{k_b}} \right)}_B}}} = {1 \over 5}

ΔTb(A)=kb(A)×\Delta {T_b}\left( A \right) = {k_b}\left( A \right) \times Molality of A

ΔTb(B)=kb(B)×\Delta {T_b}\left( B \right) = {k_b}\left( B \right) \times Molality of B

Here, Molality of A = Molality of B = m

ΔTb(A)ΔTb(B)=(kb)A(kb)B×mm{{\Delta {T_b}\left( A \right)} \over {\Delta {T_b}\left( B \right)}} = {{{{\left( {{k_b}} \right)}_A}} \over {{{\left( {{k_b}} \right)}_B}}} \times {m \over m} = 15{1 \over 5}

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