Verified Solution • 2025–26 Session moderate

QJEEM19Ch08dd: JEE Main 2019 Chemistry - Class 11 JEEM19Ch08dd Solution: For the equilibrium, 2H 2 O ⇌ H 3 O + + OH − , the value of Δ G …

For the equilibrium,
2H2O ⇌ H3O+ + OH−, the value of ΔGo at 298 K is approximately :

Multiple Choice Options

  • A − 80 kJ mol–1
  • B 100 kJ mol−1
  • C − 100 kJ mol−1
  • D 80 kJ mol–1

Step-by-Step Verified Solution

2H2O ⇌ H3O+ + OH−

Here Keq = Kw(H2O)

At 298 K, Kw(H2O) = 10-14

∴ Keq = 10-14

ΔGo = -RTln(Keq)

= -RTln(Kw)

= -2.303RT log (10-14)

= -2.303 × 8.314 × 298 × × (-14)

= 80 kJ/mol

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