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QJEEM19Ch07e4: JEE Main 2019 Chemistry - Class 12 JEEM19Ch07e4 Solution: The following ligand is :
The following ligand is :
Multiple Choice Options
- A hexadentate
- B bidentate
- C tetradentate
- D tridentate
Step-by-Step Verified Solution
Here two O- + two N = 4 donar atoms present which can donate total 4 lone pair of electrons.
It is tetradentate ligand.