QJEEM19Ch0542: JEE Main 2019 Chemistry - Class 12 JEEM19Ch0542 Solution: Adsorption of a gas follows freundlich adosorbed isotherm. x is …

According to Freundlich adsorption isotherm, in the median range of pressure

        ${x \over m} \propto {P^{{1 \over n}}}$

$\Rightarrow$    ${x \over m}$ = kP $^{{1 \over n}}$

taking log both sides, we get,

log ${x \over m}$ = logk + ${1 \over n}$ logP

Here in graph between log ${x \over m}$ and logP, slope is ${1 \over n}$ and intercepts = log k.

From the given graph,

slope = ${2 \over 3}$

$\therefore\,\,\,$ ${1 \over n}$ = ${2 \over 3}$

$\Rightarrow$    n = ${3 \over 2}$

$\therefore\,\,\,$ ${x \over m}$ = kP $^{{2 \over 3}}$

$\therefore$ ${x \over m} \propto {P^{{2 \over 3}}}$