Verified Solution • 2025–26 Session moderate

QJEEM18Phade4: JEE Main 2018 Physics - Class 12 JEEM18Phade4 Solution: A coil of cross-sectional area A having n turns is placed in a…

A coil of cross-sectional area A having n turns is placed in a uniform magnetic field B. When it is rotated with an angular velocity ω,\omega , the maxium e.m.f. induced in the coil will be:

Multiple Choice Options

  • A 3 nBA ω\omega
  • B 32{3 \over 2} nBA ω\omega
  • C nBA ω\omega
  • D 12{1 \over 2} nBA ω\omega

Step-by-Step Verified Solution

Flux in the coil, ϕ\phi = nBA sin( ω\omega t)

When n = no. of turns

              \,\,\,\,\,\,\,\,\,\,\,\,\,\, A = Area of coil

              \,\,\,\,\,\,\,\,\,\,\,\,\,\, ω\omega = angular speed

Induced emf,

∣e∣=dϕdt\left| e \right| = {{d\phi } \over {dt}}

= nBA ω\omega cos ω\omega t

∴   \therefore\,\,\, emax = nBA ω\omega

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