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QJEEM18Ph7ca8: JEE Main 2018 Physics - Class 12 JEEM18Ph7ca8 Solution: A carrier wave of peak voltage 14 V is used for transmitting a…

A carrier wave of peak voltage 14 V is used for transmitting a message signal. The peak voltage of modulating signal given to achieve a modulation index of 80% will be :

Multiple Choice Options

  • A 7 V
  • B 28 V
  • C 11.2 V
  • D 22.4 V

Step-by-Step Verified Solution

Amplitude of carrier wave is Ac = 14 V

Modulation Index is μ\mu = 80% = 0.80

Amplitude of modulating signal is given by

μ=AmAc⇒Am=μAc⇒Am=0.8×14=11.2 V\mu = {{{A_m}} \over {{A_c}}} \Rightarrow {A_m} = \mu {A_c} \Rightarrow {A_m} = 0.8 \times 14 = 11.2\,V

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