Verified Solution • 2025–26 Session moderate

QJEEM18Ph69c6: JEE Main 2018 Physics - Class 12 JEEM18Ph69c6 Solution: A heating element has a resistance of 100 at room temperature.…

A heating element has a resistance of 100 Ω\Omega at room temperature. When it is connected to a supply of 220 V, a steady current of 2 A passes in it and temperature is 500oC more than room temperature. what is the temperature coefficient of resistance of the heating element ?

Multiple Choice Options

  • A 0.5 ×\times 10 −- 4 oC −- 1
  • B 5 ×\times 10 −- 4 oC −- 1
  • C 1 ×\times 10 −- 4 oC −- 1
  • D 2 ×\times 10 −- 4 oC −- 1

Step-by-Step Verified Solution

When temperature increased by 500oC then, nrw registance

Rt = 2202{{220} \over 2} = 110 Ω\Omega

We know,

Rt = R0 (1 + ∝\propto Δ\Delta t)

⇒\Rightarrow 110 = 100 (1 + ∝\propto ×\times 500)

⇒\Rightarrow ∝\propto = 10100×500=2×10−4{{10} \over {100 \times 500}} = 2 \times {10^{ - 4}} oC −- 1

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