QJEEM18Ph46c4: JEE Main 2018 Physics - Class 12 JEEM18Ph46c4 Solution: The reading of the ammeter for a silicon diode in the given…

Note :

From the circuit you can see the diode is in forward bias, and to start current flow through the circuit. Accross silicon diode the voltage drop should be 0.7 V and for Germenium diode the voltage drop is 0.3 V. Then diode will start working and current will flow through the circuit.

So, the net voltage available accros the registor is (V_net) = 3 $$-$$ 0.7 = 2.3 V

$$\therefore$$ Current flow through circuit = $$\frac{2.3}{200}$$ = 11.5 mA